find the centroid of a triangle whose vertices are (3,4) (-7,_2) and (10,_5)
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sentromiar ka formula lagega
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hiii friend
Step-by-step explanation:
suppose ABC is vertices of a triangle
let A(x1,y1)=(3,4)
B(x2,y2)=(-7,2)
C(x3,y3)=(10,5)
we know that
by centroid formula
x=x1+x2+x3/3
=3+(-7)+10/3
=3+3/3
=2
x=2
y=y1+y2+y3/3
=
I have a now some confusion in numbers I hope u understand me
and put the value of x,y and get answer
good morning my friend
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