Question

Find the centroid of a triangle with vertices (3,5),(-14,-19) and (-1,-7) *​

Answer 1

$centroid \: of \: a \: triangle = \frac{x1 + x2 + x3}{3} \: \: \frac{y1 + y2 + y3}{3} \\ here \\ x1 = 3 \: x2 = - 14 \: \: x3 = - 1 \: \: \\ y1 = 5 \: \: y2 = - 19 \: \: y3 = - 7 \\ \frac{3 + - 14 - 1}{3} \: \: \frac{5 - 19 - 7}{3} \\ \frac{3 - 15}{3} \: \: \frac{5 - 26}{3} \: \: \\ \frac{ - 12}{3} \: \: \frac{ - 21}{3} \\ = - 4 \: \: - 7 \\ therefore \\ centroid \: of \: a \: triangle \: is \: - 4. - 7 \\ \\hope \: it \: helps \: you$