Question

find the centroid of a triangle with vertices (a, b), (b, c), (c, a).​

Answer 1

Answer:

3abc

hope this helps.☝️

Answer 2

$\huge\color{purple}\boxed{Question}$

Find the centroid of a triangle with vertices (a, b), (b, c), (c, a).

$\huge\fbox\color{Green}{Answer}$

Centeroid of a triangle is calculated by

$\large\frac{(x1+x2+x3)}{3},\frac{(y1+y2+y3)}{3}$

So,

$\large\frac{(a+b+c)}{3},\frac{(b+c+a)}{3}$ = $\large(0,0)$

$\implies$ $\large{a+b+c=0}$

$\implies$ $\large{a³+b³+c³}$= $\fbox{3abc}$