Find the centroid of the A ABC with A (-1,3) and midpoint of BC is
3/2, 3/2
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A = (2,3). Let D be the midpoint of BC. Therefore D = (-2,4). So AD is a median.
We know that the centroid of a triangle divides each median in the ratio 2:1
If G is the centroid of the Δ ABC then G can be found out by using the section formula {(mx2+nx1)/(m+n), (my2+ny1)/(m+n)}
Taking A = (2,3) as (x1, y1) and D = (-2,4) as (x2,y2), the ratio 2:1 as m:n in the formula we get G = (-2/3, 11/3)
Hence the centroid of the triangle = (-2/3, 11/3)
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