Math, asked by samiksha3886, 1 year ago

Find the centroid of the triangle whose vertices are (2,4) (6,4) (2,0)

Answers

Answered by richigupta
12

C =( x1 + x2 + x3/3 , y1 + y2 + y3/3)

Where,

C is the centroid of the triangle.

x1,x2,x3 are the x-coordinate’s of the vertices of the triangle.

y1,y2,y3 are the y-coordinate’s of the vertices of the triangle.


x1 = 2 , y1 = 4

x2 = 6 , y2 = 4

x3 = 2 , y3 = 0


C = (2+6+2/3 , 4+4+0/3)

C = (10/3 , 8/3)

Hope it helped and please mark it as Brainliest.


Answered by Anonymous
3

 \bold{Answer} \\   \green{\tt{ \therefore  coordinate\:of\:centroid = (\frac{10}{3},\frac{8}{3})}}

• From the given question :

 \bold{Step-by-step \: explanation} \\  \\  \text{According \: to \: centroid \: formula} \\   \tt  \to  x =  \frac{ x_{1} +  x_{2}  +  x_{3}  }{3}  \\  \\  \tt \to  x =  \frac{ 2+6+2}{3}  \\  \\  \tt \to x =  \frac{4+6}{3}  \\  \\   \green{\tt  \to x = \frac{10}{3}} \\  \\  \tt  \to  y =  \frac{ y_{1} +  y_{2}  +  y_{3}  }{3}  \\  \\  \tt \to  y =  \frac{ 4 +4+0}{3}  \\  \\  \tt \to y=  \frac{4+4}{3}  \\  \\  \green{\tt  \to y=  \frac{8}{3}}  \\  \\    \green{\tt{\therefore Coordinate \: of \: centroid \: is \: (\frac{10}{3}, \frac{8}{3})} }

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