Question

find the centroid of the triangle whose vertices are (3,-5),(-7,4),(10,-2)

Answer 1

hey,
The centroid of the triangle whose vertices are (3,-5),(-7,4),(10,-2) is 

∵ The centroid of the triangle ABC = (x1 + x2 + x3 / 2 , (y1 + y2 + y3 / 2) 

∴  The centroid of the triangle whose vertices A(3,-5), B(-7,4), C(10,-2) = (3-7+10 / 3 , -5 + 4 - 2 / 3)    

= (2,-1)

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Answer 2

As we know,
The formula for centroid is
=(x1+x2+x3 /3, y1 +y2 +y3 /3)
=(3-7+10/3,-5+4-2/3)
=(6/3,-3/3)
=(2,-1)
Hence, (2,-1) is the centroid of the triangle whose vertices are( 3,-5),(-7,4) and (10,-2)...

Hope it helps!!