Math, asked by mshripriya007, 1 year ago

find the centroid of the triangle whose vertices are (3,-7) ,(-8,6) and (5,10).

Answers

Answered by vishnuvardhan232
1

Hey mate refer the attachment above.

Hope it helps you and have a nice day and please mark this answer as brainliest

Attachments:
Answered by Anonymous
22

\red{\bold{\underline{\underline{Answer}}}}

\bold{\green{\therefore{Centroid=(0,3)}}}

\pink{\bold{\underline{Step-by-step\:explanation}}}

  • Given

 \tt  \implies Coordinate \: of \: p = (3,-7) \\  \\ \tt  \implies Coordinate \: of \: q= (-8,6) \\  \\ \tt  \implies Coordinate \: of \: r= (5,10)

  • To find

 \tt  \implies Centroid = ?

For finding value of centroid :

 \tt \implies x =  \frac{ x_{1} + x_{2}   +  x_{3}  }{3}  \\  \\ \tt \implies x = \frac{3-8+5}{3}  \\  \\ \tt \implies x = 0  \\  \\ \tt \implies y=\frac{ y_{1} + y_{2}   +  y_{3}  }{3} \\  \\\tt \implies y=  \frac{-7 + 6+10}{3}  \\  \\ \tt \implies y= 3  \\  \\   \green{\tt \therefore Centroid \: is \:  (0,3)}

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