Question

find the centroid of the triangle whose vertices are (3,-7),(-8,6),(5,10)

Answer 1

Centroid formula is given by
X = x1 + x2 + x3 ÷ 3
Y= y1 + y2 + y3 ÷ 3

therefore the Centroid of the triangle are...

(0,3).......

Answer 2

$\red{\bold{\underline{Answer}}}$

$\tt\green{\therefore{Centroid=(0,3)}}$

$\pink{\bold{\underline{Step-by-step\:explanation}}}$

• Given

$\tt \implies Coordinate \: of \: p = (3,-7) \\ \\ \tt \implies Coordinate \: of \: q= (-8,6) \\ \\ \tt \implies Coordinate \: of \: r= (5,10)$

• To find

$\tt \implies Centroid = ?$

For finding value of centroid :

$\tt \implies x = \frac{ x_{1} + x_{2} + x_{3} }{3} \\ \\ \tt \implies x = \frac{3-8+5}{3} \\ \\ \tt \implies x = 0 \\ \\ \tt \implies y=\frac{ y_{1} + y_{2} + y_{3} }{3} \\ \\\tt \implies y= \frac{-7+6+10}{3} \\ \\ \tt \implies y= 3 \\ \\ \green{\tt \therefore Centroid \: is \: (0,3)}$