Question

Find the centroid of the triangle whose vertices are (4,0), (0, -6) and (2,6).​

Answer 1

Answer:

Centroid of the triangle (2,0)

Step-by-step explanation:

Formula for the centroid of the triangle is [X1+X2+X3/3,Y1+Y2+Y3/3]

On x-axis;

X1=4, X2=0 and X3=2

So;

=4+0+2/3

=6/3

=2

On Y-axis:

Y1=0, Y2= -6 and Y3=6

So;

=0-6+6/3

=0/3

=0

Hence;the centroid of the triangle is (2,0)

Answer 2

$\red{\bold{\underline{\underline{Answer}}}}$

$\mathfrak\green{\therefore{Centroid=(2,0)}}$

$\pink{\bold{\underline{Step-by-step\:explanation}}}$

• Given

$\tt \implies Coordinate \: of \: p = (4,0) \\ \\ \tt \implies Coordinate \: of \: q= (0,-6) \\ \\ \tt \implies Coordinate \: of \: r= (2,6)$

• To find

$\tt \implies Centroid = ?$

For finding value of centroid :

$\tt \implies x = \frac{ x_{1} + x_{2} + x_{3} }{3} \\ \\ \tt \implies x = \frac{4+0+2}{3} \\ \\ \tt \implies x = 2 \\ \\ \tt \implies y=\frac{ y_{1} + y_{2} + y_{3} }{3} \\ \\\tt \implies y= \frac{0 -6+6}{3} \\ \\ \tt \implies y= 0 \\ \\ \green{\tt \therefore Centroid \: is \: (2,0)}$