Math, asked by Sadvik, 1 year ago

find the centroid of the triangle whose vertices are(-4,6)(2-2)and(2,5)

Answers

Answered by BrainlyConqueror0901
37

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{Centroid(G)=}(0,3)}}\\

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{ \underline  \bold{Given : }} \\   : \implies  \text{Coordinate \: of \: A = (-4,6)} \\  \\ : \implies  \text{Coordinate \: of \: B = (2,-2)} \\  \\ : \implies  \text{Coordinate \: of \: C = (2,5)} \\  \\ \red{ \underline  \bold{To \: Find : }} \\   : \implies \text{Centroid(G) = ?}

• According to given question :

 \bold{As \: we \: know \: that} \\  \circ  \:   \text{Centroid \: of \: triangle(G}) \\ \\  \circ \:   \text{For \: x  }= \frac{ x_{1} +  x_{2} +  x_{3}  }{3}  \\  \\ \circ \:   \text{For \: y} = \frac{ y_{1} +  y_{2} +  y_{3}  }{3}  \\  \\  \text{Let \: Coordinate \: of \: (g) =( x,y) } \\ \\   \bold{For \: x}\\   :  \implies x = \frac{ x_{1} +  x_{2} +  x_{3}  }{3} \\  \\   : \implies x =  \frac{  -4 +2 + 2}{3} \\  \\ : \implies x = \frac{-4+4}{3}  \\  \\  \green{: \implies x =0} \\  \\  \bold{For \: y}\\   :  \implies y= \frac{ y_{1} +  y_{2} +  y_{3}  }{3} \\  \\   : \implies y=  \frac{ 6  +(-2)+5}{3} \\  \\ : \implies y = \frac{11-2}{3}  \\  \\  \green{: \implies y =3} \\  \\    \green{\therefore  \text{Coordinate \: of \: centroid(G) = }(0,3)}

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