Question

Find the centroid of the triangle whose vertices are A(2,-1), B(5,-4),C(8,-7).​

Answer 1

Step-by-step explanation:

Given:-

vertices are A(2,-1), B(5,-4),C(8,-7).

To find:-

Find the centroid of the triangle whose vertices are A(2,-1), B(5,-4),C(8,-7).

Solution:-

Given vertices are A(2,-1), B(5,-4),C(8,-7).

Let (x1, y1)=A(2,-1)=>x1=2 and y1=-1

Let (x2, y2)=B(5,-4)=>x2=5 and y2=-4

Let (x3,y3)=C(8,-7)=>x3=8 and y3=-7

we know that the centroid of a triangle whose formed by the vertices (x1, y1);(x2, y2) and (x3, y3) is [(x1+x2+x3)/3 , (y1+y2+y3)/3]

=>[(2+5+8)/3 , (-1-4-7)/3]

=>(15/3 , -12/3)

=>(5,-4)

Centroid = (5,-4)

Answer:-

Centroid of the given triangle is (5,-4)

Used formula:-

• The concurrent point of the medians of the triangle is called the centroid of the triangle.
• (x1, y1);(x2, y2) and (x3, y3) are the vertices of a triangle then the centroid of the triangle is denoted by G(x,y) and it is defined by [(x1+x2+x3)/3 , (y1+y2+y3)/3]