find the centroid of triangle ABC whose vertices are (-1,0),B(5,-2),and C(8,2).
Answers
Answered by
5
centroid of a triangle ABC is equals to x=(X1+X2+X3)/3
so (-1+5+8)/3=4
y=(Y1 + Y2 + y3) / 3
so (0-2+2)/3=0
then centroid will be (4,0).
so (-1+5+8)/3=4
y=(Y1 + Y2 + y3) / 3
so (0-2+2)/3=0
then centroid will be (4,0).
Similar questions