find the centroid of triangle ABC whose vertices are A(2,2) B(-4,-4) and C(5,-8)
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1
Answer:
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Answered by
2
Answer:
-10/3
Step-by-step explanation:
A(2,2) B(-4,-4) C(5,-8)
Centroid of triangle = ((x₁+x₂+x₃/3)( y₁+y₂+y₃/3))
x₁=2; x₂=-4; x₃=5
y₁=2; y₂=-4; y₃=-8
centroid of triangle
=( (2+(-4)+5/3) (2+(-4)+(-8)) )
=( (2-4+5/3) (2-4-8/3) )
=( (3/3) (-10/3) )
=( (1) (-10/3) )
=-10/3
hope you understand
if this answer is wrong please tell me the correct answer...
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