Question

Find the centroid of triangle PQR whose vertices are P(1,1) ,Q(2,2) ,R(-3,-3)​

Answer 1

Answer:

centroid of the triangle = (0,0)

Step-by-step explanation:

GIVEN:

P(1,1)

Q(2,2)

R(-3,-3)

Centroid of triangle = ( x1 + x2 + x3 /3  , y1 + y2 + y3 /3 )

                                 = (1 + 2 +(-3) / 3 , 1 + 2 + (-3) / 3 )

                                 =( 3 - 3 / 3 , 3 - 3 / 3 )

                                  = (0/3 , 0/3)

                                  = (0 , 0)