Find the chance of throwing 10 exactly in one throw of 3 dice.
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Step-by-step explanation:
With 3 dices 10 can be thrown in the follwing ways
1) 631 - This can happen in 3!=6 ways
2) 622 - This can happen in
2!
3!
=3 ways
3) 541 - This can happen in 3!=6 ways
4) 532 - This can happen in 3!=6 ways
5) 442 - This can happen in
2!
3!
=3 ways
6) 433 - This can happen in
2!
3!
=3 ways
∴ Total number of favourable cases =6+3+6+6+3+3=27
Also, Total number of cases =6
3
=216
∴ Required Probability =
216
27
=
8
1
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