Question

Find the chance of throwing more than 9 in one throw with 2 dice.

Answer 1

there 2 chance if throwing more than 9 in one throw with 2 dice they are 3 and 6 or 5 and 4

Answer 2

Throwing more than 9 when we throw two dice =Total favorable outcome

         = (6,4),(4,6),(6,5),(5,6),(5,5) ,(6,6)= 6 in number

Total possible outcome when we throw two dice together = 6²= 36

Probability of an event = $\frac{\text{Total favorable outcome}}{\text{Total possible outcome}}$

Probability of throwing more than 9 in one throw with 2 dice= $\frac{6}{36}$ = $\frac{1}{6}$