Find the change in a number which is first increased by 20% and then decreased by 20%.
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If the no. is x, then after this process the no. will change to 6x/25
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Let no be X
If it is first increased by 20%
X + [ (X*20)/100 ] = (X*120)/100
If it is decreased by 20%
(120*X)/100 - (120*X*20)/100 = (120*80*X)/100
= (96*X)/100
change in the number
= X - (96*X)/100
= (4*X)/100
So, the change(reduction) in the number will be 4%
If it is first increased by 20%
X + [ (X*20)/100 ] = (X*120)/100
If it is decreased by 20%
(120*X)/100 - (120*X*20)/100 = (120*80*X)/100
= (96*X)/100
change in the number
= X - (96*X)/100
= (4*X)/100
So, the change(reduction) in the number will be 4%
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