Question

Find the change in electrical potential energy, when a charge of 2.4 × 10– 5 C is moved from P to Q. (Given VQP = 12 V).........

Answer 1

Answer:

$2.88 *10^{-4}$

Explanation:

Change in energy = ΔE =Work done

W = QV = $2.4 *10^{-5} *12 =28.8*10^{-5} = 2.88*10^{-4}$ Joule