Question

Find the change in internal energy in joule. When 10g of air is heated from 30c to 40c

Answer 1

Answer :

The change in internal energy in Joule is 72.24 J

Step-by-step explanation :

Given,

Mass of air = 10g

Since 1 g = 1 * $10^{-3}$ kg

So 10 g = 10 * $10^{-3}$ kg

Mass of air =  10 * $10^{-3}$ kg

Given,

Air is heated from 30c to 40c

We know,

0°C + 273.15 = 273.15K  , that is ,

30°C  in Kelvin = 30 + 273.15 = 303 K

40°C  in Kelvin = 40 + 273.15 = 313 K

So ,

Δ T = 313 - 303 K = 10 K

We know

$C_{v}$  = 0.172kcal / kg K and

J = 4200J / k.cal

Now,

Change in internal energy  $(dQ)_{v}$  = m * $C_{v}$  * Δ T

$(dQ)_{v}$  =  10 * $10^{-3}$  * 0.172 * 4.2 * 10³ * 10

$(dQ)_{v}$ = 17.2 * 4.2

$(dQ)_{v}$ = 72.24 J

Hence,

The change in internal energy in Joule is 72.24 J

Answer 2

Answer:

the answer for this question is 72.24 joules