Find the change in internal energy of the system in which 1200 calories is removed from a gas held at constant volume (give your answer in kilojoules)
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volume is constant hence Δw=0
therefore ΔQ=ΔU
ΔQ= 1200 x 4.2 x j
ΔQ=5040j
ΔU=5.040 kj
if i m not wrong
therefore ΔQ=ΔU
ΔQ= 1200 x 4.2 x j
ΔQ=5040j
ΔU=5.040 kj
if i m not wrong
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