Question

find the change in momentum of a loaded truck weighing 5000 kg moving at 54 km / hr when tow boxes of bananas weighing 100 kg each drip off in the road​

Answer 1

Hii its tom85

initial

m= 5000

v= 54km/hr = 54*5/18 = 15m/s

final

m1= 4800

v= 15m/s

now change in mass = 200kg

change in momentum =

v(change in mass ) = 200*15

= 3000kgm/s

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Hope it may helps you

Answer 2

ANSWER:

change in momentum of truck = 3000 kgm/s

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Explanation:

given that,

truck weighing 5000 kg moving at 54 km / hr

so,

here,

mass of car = 5000 kg

velocity of moving = 54 km/h

changing of velocity in km/h into m/s

= 54 × 1000/60 × 60

= 15 m/s

momentum of truck = mass of truck × velocity at which truck is moving

putting the values,

momentum = 5000 kg × 15  m/s

=  75000 kgm/s

let the momentum 75000 be initial momentum

now,

also,

given that,

two boxes of bananas weighing 100 kg each drip off in the road

so,

mass of two boxes = 200 kg

velocity of boxes when it drip off in the road = same as the truck I.e. 54 km/h = 15 m/s

now,

mass of both boxes = 200 kg

velocity = 15 m/s

momentum of the boxes =

mass of the boxes × velocity of the boxes .

putting the values,

200 kg × 15 m/s

= 3000 kgm/s

now,

momentum of truck = momentum of truck with two boxes - momentum of the two boxes

momentum of truck with two boxes = 75000 kgm/s

momentum of the two boxes =

3000 kgm/s

putting the values,

75000 kgm/s - 3000 kgm/s

= 72000 kgm/s

let the momentum 72000 kgm/s be final momentum.

now,

change in momentum = initial momentum - final momentum  [larger momentum - smaller momentum ]

putting the values,

75000 kgm/s - 72000 kgm/s

= 3000 kgm/s

so,

change in momentum of truck

= 3000 kgm/s