Question

find the change in ph when 0.01 mole ch3coona is added to one litre of 0.01m ch3cooh solution pka= 4.74

Answer 1

Given:

$pK_a$ = 4.74

Conc. of salt ($CH_3COONa$) = 0.01M

Conc. of acid ($CH_3COOH$) = 0.01 M

To find:

Change in pH = ?

Formula to be used:

Herderson - Hasselblach formula

Calculation:

By using the Herderson - Hasselblach formula, it gives

pH = $pK_a+log\frac{Conc. of salt}{Conc. of acid}$

pH = 4.74 + log $\frac{0.01}{0.01}$

pH = 4.74

Conclusion:

As pH value and $pK_a$ value are same, it means that the concentration is same and there is no change in the pH.

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