find the change in volume per unit volume due to uniaxial tension loading on a block.where 'qx' is strain in direction of loading and 'v' is poisson's ratio.
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Explanation:
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Given:
Poisson's ratio 0.2.
longitudinal strain 4.0×10−3
As σ=−Δl/lΔR/R
∴RΔR=−σlΔl=−0.2×4.0×10−3=−0.8×10−3
V=πR2l
∴VΔV×100=(2RΔR+lΔl)×100=[2×(−0.8×10−3)+4.0×10−3]×100=2.4×10−3×100=0.24%
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