Question

Find the charge of 1 g-ion of N3- in Coulombs.?

Answer 1

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For 1 g-ion. 1 g-ion = (weight in grams of sum of atomic weight of atoms making the ion.)

Here N^3- has 14 amu so 1g-ion 14 gm.

So here we have to find for 14g that is 1mole of nitride ion. 1 ion of nitride has =1.6 ×10^-19 × 3 C

Therefore 6.022 × 10^23 ions has = 6.022 × 10^23 ×1.6 ×10^-19 × 3 C = 2.89 × 10^5 C.

Answer 2

Step 1: Given data

Charge on $1g$ of $N^{3-}=?$

Step 2: Calculating the charge

We know that,

charge on one electron$=1.6\times 10^{-19} C$

charge on one ion of  $N^{3-}=3\times 1.6\times 10^{-19} C$

So, $1g$ ion$=6.022\times 10^{23}$ ions

Now, charge on  $1g$ of $N^{3-}$ is calculated as,

$=3\times 1.6\times 10^{-19}\times 6.022\times 10^{23} C$

$=2.89\times 10^{5} C$

Hence, the charge on  $1g$ of $N^{3-}$ is $2.89\times 10^{5} C$.

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