Find the charge of 48 gm of Mg2+ ions in coulombs
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moles of Mg in 48 gm = 2moles
charge on 1 Mg2+ = 2 × 1.6 × 10^–19C
charge on two moles of Mg2+ =
=2× 6.022×10^23 × 2×1.6×10^–19C
= 6.4 × 6.022 × 10^4 C
= 3.854 × 10^5 C.
charge on 1 Mg2+ = 2 × 1.6 × 10^–19C
charge on two moles of Mg2+ =
=2× 6.022×10^23 × 2×1.6×10^–19C
= 6.4 × 6.022 × 10^4 C
= 3.854 × 10^5 C.
gauravnsharma31:
thnx mahn
np bro
that was easy
so no problem
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