find the charges in the length of a second`s pendulum if the acceleration due to gravity at place change from 9.75 m/s^2 to 9.8 m/s^2
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Answer:
Time period will be doubled
Time period with acceleration due to gravity g
T
1
=2π
g
l
for a second's pendulum time period is 2s
when acceleration is one -fourth
T
2
=2π
4
g
l
=2×2π
g
l
=2×T
1
=4×2=4s
Explanation:
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