Physics, asked by jatinchaudhary4291, 8 months ago

Find the charges on three capacitors

Answers

Answered by GRANDxSAMARTH
5

The capacitances of three capacitors are C1= 2 μF, C2= 4 μF and C3= 6 μF and the voltage of the battery (V) is 12 V.

As the capacitors are connected in parallel, the equivalent capacitance is given by

Ceq = C1 + C2 + C3

= (2 + 4 + 6) μF = 12 μF = 12 × 10−6 F

Due to parallel connection, the potential difference across each capacitor is the same and is equal to 12 V.

Therefore, the charge on each capacitor can be calculated as follows:

The charge on the capacitor of capacitance C1= 2 μF is given by

Q1 = C1V = (2 × 10−6) × 12 C = 24 × 10−6 C = 24 μC

Similarly, the charges on the other two capacitors are given by

Q2 = C2V = (4 × 10−6) × 12 C = 48 × 10−6 C = 48 μC

and

Q3 = C3V = (6 × 10−6) × 12 C = 72 × 10−6 C = 72 μC

#Note:-See the diagram in photo

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