find the charges on three capacitors
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C
1
=2μF,C
2
=4μF
C
3
=6μF V=12V
C
eq
=C
1
+C
2
+C
3
=2+4+6=12μF
Charge is obtained as:
q
1
=12×2=24μC,
q
2
=12×4=48μC,
q
3
=12×6=72μC
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