Question

Find the chord AB of the circle AC is diameter which is 8√3 and o is the circle .​

Answer 1

Answer:

Let AB be the chord of the given circle with centre O and a radius of 10 cm.

Then AB =16 cm and OB = 10 cm

From O, draw OM perpendicular to AB.

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ BM = 162 cm=8 cm

In the right ΔOMB, we have:

OB2= OM2 + MB2 (Pythagoras theorem)

⇒ 102 = OM2 + 82

⇒ 100 = OM2 + 64

⇒ OM2 = (100 - 64) = 36

⇒ OM=36 cm=6 cm

Hence, the distance of the chord from the centre is 6 cm.