Question

Find the CI at the rate of 14% per annum for 1 year on a sum of 12,000 compounded half-yearly.​

Answer 1

Given:

Principal (P) = ₹12,000

Rate% (R) = 14% p.a.

Time (T) = 1 year

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To find:

Compound Interest (C.I.)

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Solution:

In order to find compound interest, first we will find the amount (A).

As we have to find C.I. compounded half yearly, so,

Principal = ₹12,000

Rate% = $\dfrac {14}{2}$% = 7% p.p.

Time = 2 half years (since there are two six months or half years in a year).

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As we know that,

$A = P(1 + \dfrac{R}{100})^{n}$

$A= 12000(1 + \dfrac{7}{100})^{2}$

$A= 12000( \dfrac{100 + 7}{100})^{2}$

$A= 12000( \dfrac{107}{100})^{2}$

$A = \dfrac{12000 \times 107 \times 107}{100 \times 100}$

$\boxed {\sf {\pink {A = ₹13,738.8}}}$

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Now,

C.I. = A-P

So,

C.I. = ₹(13,738.8-12,000)

$\boxed {\sf {\blue {C.I. = ₹1,738.8}}}$

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Final answer:

The C.I. at the rate of 14% per annum for 1 year on a sum of 12,000 compounded half-yearly is $\boxed {\sf {\green {₹1,738.8}}}$

Answer 2

Step-by-step explanation:

Here is the answer.I haven't copied the first answer I have done own by me.... Please give Thanks:)