Question

Find the CI on 2,500 at 10% per annum compounded annually for 2.5
years.
​

Answer 1

Answer:

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Step-by-step explanation:

$principal = 2500 \\ rate \: of \: intrest = 10\% \\ time = 2.5yrs \\ we \: know \: that - \\ a = p(1 + 10 \div 100) ^{2} \\ = 2500(1 + 10 \div 100) ^{2} \\ = 2500(1 + 0.1) ^{2} \\ = 2500 \times 1.1 \times 1.1 \\ = 3025 \\ \: now \: rs3025 \: becomes \: the \: principal \: at \: the \: end \: of \: 2nd \: year \\ si = p \times r \times t \div 100 \\ = 3025 \times 0.5 \times 10 \div 100 \\ = 151.25 \\ so \: interest \: of \: rs \: 2500 \: at \: rate \: of \: 10\% \: fr \: the \: first \: year \: = \:r s \: 250 \\ intrest \: of \: rs \: 2500 + 250 = rs2750 \\ so \: total \: ci \: \\ = 250 + 151.25 + 2700 \\ = rs \: 3151.25 \: answer$

Answer 2

Answer:

principal=2500

rateofintrest=10%

time=2.5yrs

weknowthat−

a=p(1+10÷100)

2

=2500(1+10÷100)

2

=2500(1+0.1)

2

=2500×1.1×1.1

=3025

nowrs3025becomestheprincipalattheendof2ndyear

si=p×r×t÷100

=3025×0.5×10÷100

=151.25

sointerestofrs2500atrateof10%frthefirstyear=rs250

intrestofrs2500+250=rs2750

sototalci

=250+151.25+2700

=rs3151.25answer