find the ciordinates of A .
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find the co-ordinate of a point a where ab is the diameter of circle whose Centre is (2,-3) and b is (1,4)
Solution
Given,
- Ab is diameter of the circle whose Centre is (2,-3) and point b (1,4)
To find ,
- we have to find here the coordinates of the point A .
Let the circle be shown with centre c(2,-3)
Let ab be the diameter of the circle .
Since AB is the diameter ,
Centre C must be the midpoint of AB .
- Let A(X,y)
Since , she is the midpoint of AB .
- x- co-ordinate of c = x1 + x2 / 2
- Y co-ordinate of c = y1 +y2 / 2
Where ,
- x1 = X , y1 = y
- x2 = 1 , y2 = 4
So,
X - co-ordinate of c = X+1/2
_________________________
=> 2 = X+1/2
=> 2×2=X+1
=> 4= X+1
=> X = 4-1
=> X = 3
Y - co-ordinate of c = y +4/2
___________________________
=> -3 = y+4/2
=> -3×2 = y+4
=> -6 = y +4
=> -6-4= y
=> -10 = y
Hence, the co-ordinate of A(X,y) = A(3,-10)
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