Math, asked by IntrovertLeo, 5 months ago

find the circle and heart​

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Answers

Answered by SweetestBitter
37

\begin{gathered}\large {\boxed{\sf{\mid{\overline {\underline {\star ANSWER ::}}}\mid}}}\end{gathered}

To Find :-

The value of Circle and Heart.

Solution :-

Let ❍ = x and ♡ = y

Sum of all figures = 44

x + x + y + 6 + 6 = 44

2x + y + 12 = 44

2x + y = 44 - 12

2x + y = 32 ..eq 1

Also, to be noted that both the side are balanced :

x + x = y + 6 + 6 = 44/2

2x = y + 12 = 22

x = 22/2 and y = 22 - 12

 \large \boxed{x = 11 \: and \: y = 10}

Verification :

Substituting the values of x and y in Eq.1 :

2x + y = 32

2(11) + 10 = 32

22 + 10 = 32

32 = 32

Hence, the values of x and y found are correct.

Final Answer :

\large \boxed{❍ = x \: and \: ♡ = y }

@SweetestBitter

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Answered by KingIshant
12

_______________________

㋛︎ = x ✔︎

( ans )

❤︎ = y . ✔︎

_______________________

To Find : -

The value of circle and heart .

Let ㋛︎ = x and

❤︎ = y .

➪ Sum of all figures = 44

=> x + x + y + 6 + 6 = 44

=> 2x + y = 44 - 12

=> 2x + y = 22 __ i)

Given that, both sides are balanced

 =  > x + x = y + 6 + 6 =  \frac{44}{2}

=> 2x = y + 22 - 12

 =  > x =  \frac{22}{2}

=> y = 22 -12

x = 11

y = 10

_______________________

Putting the values of x and y in Eq. 1 we get ,

2x + y = 32

=> 2 ( 11 ) + 10 = 32

=> 22 + 10 = 32

=> 32 = 32

_______________________

The Required answer

㋛︎ = x

❤︎ = y

______________________

꧁☯︎F҉O҉L҉L҉O҉W҉ M҉E҉☯︎꧂❤️❤️❤️❤️

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