Question

find the circumcenter of a triangle whose sides are 3x-y-5=0 ,x+2y-4=0,5x+3y+1=0​

Answer 1

Answer:

A

3x-y-5=0

y=3x-5

B

x+2y-4=0

y=-1/2x+2

C

5x+3y+1=0

y=-5/3x-1/3

D

3x-5=-1/2x+2

D(2,1)

E

3x-5=-5/3x-1/3

(1,-2)

F-1/2x+2=-5/3x-1/3

(-2, 3)

use these point to make a circle.

D=(2-h) ^2+ (1-k) ^2=r^2

E=(1-h) ^2+(-2-k) ^2=r^2

F=(-2-h) ^2+(3-k) ^2=r^2

h=-6/7, k=2/7, r=5√17/7

circumcenter=-(6/7, 2/7y)