Question

Find the circumcenter of the triangle formed by the straight lines x+y = 0, 2x+y + 5 = 0 and
x-y=2. ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

First take,

x+y=0.......eq.1

2x+y +5=0.......eq.2

x-y=2........eq.3

solve eq 1 and eq 2 ,

we get vertex of A ( -5,5 )

Solve eq.2 and eq.3 ,

we get vertex B (-1,-3)

Solve eq.3 and eq.1 ,

we get vertex C (1,-1)

let circumference of S be x and y,

so SA =SB=SC

Now solve SA=SB......(using distance formula),

we get x-2y+5=0.........eq.4

Solve SA=SC,

we get x-y-2+4=0.......eq.5

x=3 and y=1

Hence the circumference (S)of the triangle will be

-3 and 1