find the circumcenter of the triangle whose sides are 3x-y=0;x+2y-4=0;5x+3y+1=0;
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Answer:
Circumcenter = (−6/7,2/7 )
Step-by-step explanation:
=> A
3x − y − 5 = 0
⇒y = 3x − 5
=> B
x + 2y − 4=0
y = −1/2x + 2
=> C
5x + 3y + 1 = 0
y = −5/3x − 1/3
=> D
3x−5 = −1/2x + 2
⇒D(2,1)
=> E
3x−5 = –5/3x – 1/3
⇒E(1,−2)
=> F
−1/2 x+2 = −5/3 x− 1/3
⇒F(−2,3)
• Use these point to make a circle.
D = (2−h)² + (1−k)² = r²
E = (1−h)² + (−2−k)² = r²
F = (−2−h)² + (3−k)² = r²
⇒h = −6/7,k = 2/7,r = 5√17/5
Circumcenter = (−6/7,2/7 )
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