Question

find the circumcentre of the triangle whose sides are 3x-y-5=0, x+2y-4=0, and 5x+ 3y+1=0​

Answer 1

Answer:

3x- y - 5 = 0

solve for x

3x - y - 5 = y

3x- 5 = y

3x= y + 5

3x / 3 = y + 5 / 3

x = y + 5 / 3

solve for y

- y - 5 = - 3 x

- y = - 3x + 5

- y = 5 - 3x

- y / - 1 = 5 - 3x / - 1

y = 5 - 3x / -1

y = 3x - 5

x + 2y - 4 = 0

solve for x

x - 4 = - 2y

x = - 2 y + 4

solve for y

2y - 4 = - x

2y = - x + 4

2y = 4 - x

2y / 2 = 4 - x / 2

y = 4 - x / 2

y = - x /2+2

5 x + 3y + 1 = 0

solve for x

5x + 1 = - 3y

5 x = - 3y - 1

5x/ 5 = - 3y - 1 / 5

x = - 3y - 1 /5

solve for y

3y + 1 = - 5 x

3y = - 5x - 1

3y / 3 = - 5 x - 1 / 3

y = - 5 x - 1 / 3

Answer 2

your answer is in the attachment ↑

hope it helps

please mark me as brainliest