Question

Find the circumcentre of the triangle whose sides are given by x+y+2=0, 5x-y-2=0 and x-2y+5=0.

Answer 1

Let ABC be the triangle.

Side AB=x+y+2=0

BC=5x-y-2=0

CA=x-2y+5=0

solve x+y+2=0 and x-2y+5=0

you get x=-3,y=1 these are the co-ordinate of A

similarly find coordinates of B=0,-2 and C=1,3

let the co-ordinate of circumcenter P be x,y

PA=PB

(x+3)2+(y-1)2=(x-0)2+(y+2)2

similarly equate PB=PC

you will get similar equation solve

• these two equations you will get values of x and y