Find the circumcentre of the triangle whose vertices are (1,3), 0, 2) and (5,-1)
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Let A(1,3),B(0,-2),C(-3,1). Slope of AB=(-2–3)/(0–1) =-5/-1=5. Mid point of AB ( (1+0)/2,(3–2)/2 ) = (1/2,1/2). Solving (1) and (2) we get x=-1/3 and y = 2/3
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