Find the circumcentre of the triangle with vertices ( 0,0), (3,0) and (0,4)
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Answered by
25
here's your answer dude.
because itz coordinate geomectry...
let A (0,0)be(x1,y1) and B (3,0) (x2,y2) and C(0,4) (x3,y3) find circumcentre (x,y)
by centroid formula...
x=x1+x2+x3÷3 and y=y1+y2+y3÷3
x=0+3+0÷3 and y=0+0+4÷3
x=1 and y=4÷3
therefore, circumcentre (x,y) is (1,4÷3)
hope it helpz u mark as brainliest
because itz coordinate geomectry...
let A (0,0)be(x1,y1) and B (3,0) (x2,y2) and C(0,4) (x3,y3) find circumcentre (x,y)
by centroid formula...
x=x1+x2+x3÷3 and y=y1+y2+y3÷3
x=0+3+0÷3 and y=0+0+4÷3
x=1 and y=4÷3
therefore, circumcentre (x,y) is (1,4÷3)
hope it helpz u mark as brainliest
Answered by
20
Answer:
Step-by-step explanation:
The given points when plotted show a right angled triangle
Since we know that the circumcentre of a right angled triangle lies on the midpoint of the hypotenuse, using section formula:
C=(3/2,4/2) => (3/2,2)
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