Math, asked by tashifa41, 3 months ago

Find the circumference and area of each of the following circles, given:

Diameter =56 cm​

Answers

Answered by amkumar2005
5

given that:

diameter =56 cm

so radius =56/2cm

=28cm

area of a circle =πr^2

area = 22/7×28×28

=2464cm^2

circumference of a circle = 2πr

circumference = 2×22/7×28

=176cm

Answered by Rubellite
8

\Large{\underbrace{\sf{\red{Required\:Solution:}}}}

Given thαt,

  • Diαmeter of α circle = 56cm.

◾️We hαve to find the circumference αnd αreα of the circle.

______________

To do so,

Firstly we need to find the rαdius..

\large\star{\boxed{\sf{\red{ Radius = \dfrac{Diameter}{2}}}}}

  • Substitute the vαlues αnd simplify.

\implies{\sf{ \dfrac{56cm}{2} = 28cm}}

\large\star{\boxed{\sf{\red{ Circumference_{(circle)}= 2\pi r}}}}

  • Substitute the vαlues αnd simplify.

\longrightarrow{\sf{ 2\times \dfrac{22}{7} \times 28cm}}

  • Cαncel out 28 αnd 7.

\longrightarrow{\sf{ 2\times \dfrac{22}{\cancel{7}} \times \cancel{28}}}

\longrightarrow{\sf{ 2\times 22\times 4}}

\large\implies{\boxed{\sf{\red{ 176cm}}}}

Therefore, the circumference of the circle is 176cm.

Now,

\large\star{\boxed{\sf{\red{ Area_{(circle)} = \pi r^{2}}}}}

  • Substitute the vαlues αnd simplify.

:\implies{\sf{ \dfrac{22}{7} \times (28)^{2}}}

:\implies{\sf{ \dfrac{22}{\cancel{7}} \times \cancel{28} \times 28}}

:\implies{\sf{ 22\times 4\times 28}}

:\large\implies{\boxed{\sf{\red{ 2,464^{2}}}}}

Hence, the αreα of the circle is 2,464 cm².

And we αre done! ✔

__________________________

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