Question

find the circumference of the circle inscribed in a square of side 2a units​

Answer 1

Answer :

✰required answer:

the diameter of inner circle is 2a

the radius is a

the diameter of outer circle is[tex] \sqrt[2]{2a} [\tex]

the radius \sqrt[2]{2a}

the circumference of inner circle is 2\pi \: r

{2\pi \: (2a) = 2\pi \: a

the circumference of outer circle is 2\pi \: r

{2\pi \: (2\ \sqrt{2a} ) = 4 \sqrt{2\pi \: a}

the ratio of circumference is {4\pi a}^{2} :\sqrt[4] {{2\pi a} }^{2}

{1: \sqrt{2}

the area of inner circle is { \pi r}^{2}

{\pi(2a)}^{2} = {4\pi a}^{2}

the area of outer circle is { \pi r}^{2}

\pi \ ( {\sqrt[2]{2} }^{2} = {8\pi a}^{2}

the ratio of areas is{4\pi a}^{2} : {8\pi a}^{2} =1:2

Answer 2

Answer:

find the circumference of the circle inscribed in a square of side 2a units