Question

Find the circumference of the circle whose area is equal to the sum of the areas of three circles with radius 2cm, 3cm and 6cm

Answer 1

Answer:

44 cm

Step-by-step explanation:

area of required circle = πr^2

area of 1st circle

$area \: of \: 1st \: circle \\ = \pi {(2})^{2} = 4\pi \\ area \: of \: 2nd \: circle \\ = \pi {(3)}^{2} = 9\pi \\ area \: of \: 3rd \: circle \\ = \pi {(6)}^{2} = 36\pi$

sum of areas of three circle = area of required circle

$4\pi + 9\pi + 36\pi = \pi {r}^{2} \\ 49\pi = \pi {r}^{2} \\ {r}^{2} = 49 \\ r = \sqrt{49} = 7$

radius of required circle is 7 cm

circumference of the required circle = 2πr

$= 2 \times \frac{22}{7} \times 7 \\ = 2 \times 22 \\ = 44cm$

circumference of the required circle is 44 cms

hope you get your answer

Answer 2

Answer:

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