Question

Find the circumference of the circle whose area is equal to the sum of the areas of three
circles with radius 2 cm, 3 cm and 6 cm.​

Answer 1

Step-by-step explanation:

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Answer 2

$\large{ \underline{ \mathcal{Answer - }}}$

$\: \: \: \: \: \: \: \implies{ \sf{44}}$

$\large{ \underline{ \mathcal{Explaination - }}}$

$\: \: \: \: \: \: \: \implies{ \sf{ {r}^{2} = {2}^{2} + {3}^{2} + {6}^{2} }}$

$\: \: \: \: \: \: \: \implies{ \sf{ {r}^{2} = 49}}$

$\: \: \: \: \: \: \: \implies{ \sf{ {r}^{} = \sqrt{49} }}$

$\: \: \: \: \: \: \: \implies{ \sf{ {r}^{} = 7 }}$

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Circumference =

$\: \: \: \: \: \: \: { \sf{ \boxed{2\pi \: r}}}$

$\: \: \: \: \: \: \: \implies{ \sf{ {2 \times \frac{22}{7} \times 7 }}}$

$\: \: \: \: \: \: \: \implies{ \sf{ {44 }}}$