Question

find the circumference of the the triangle whose vertices are (- 2,- 3) (- 1,0) and (7, - 6)​

Answer 1

Answer:

$= >$

[refer the attachments ]

vertices of triangle are

A(-2,-3)

B(-1,0)

C(7,-6)

Distance between AB=

$\sqrt{( {y2 - y1})^{2} + {(x2 - x1)}^{2} }$