find the class size if the class mark of the frequency distribution are 6,10,14,18,22,26and30
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Solution :
Class size( h )
= Difference of any two
consecutive class marks
= 10 - 6
h = 4
i ) Lower limit = xi - h/2
= 6 - 4/2
= 6 - 2
= 4
Upper limit = xi + h/2
= 6 + 4/2
= 6 + 2
= 8
Therefore ,
4 - 8 ,
8 - 12
12 - 16
16 - 20
20 - 24
24 - 28
28 - 32
••••
class Interval
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