Question

find the Co ordinate of point on the x axis which are at a distance of 17 units from the point (11,-8)
$0 = x {}^{2} - 121x - 203$

Answer 1

A(11,-8) and B(x,0)
AB = 17
SBS
AB^2= 289
(x-11)^2 + (0+8)^2= 289
x^2+121-22x+64=289
x^2-22x-104=0
x^2-26x+4x-104=0
x(x-26) +4(x-26) =0
(x+4) (x-26) =0
x=-4. x=26