Find the co-ordinate of point p which divides the joint a(-2,5) and b(3,-5) in ratio 2:3
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X = m1x2 + m2x1 ÷ m1 + m2
X = 2×3 + 3×(-2) ÷ 2+3
x = 6 - 6 ÷ 5
X = 0÷5
X = 0
Y = m1y2 + .m2y1 ÷2 + 3
Y = 2(-5) + 3×5 ÷ 2+3
Y = -10 + 15 ÷ 5
Y = 5 ÷ 5
Y = 1
The Coordinate of point P are ( 0 , 1 ).
Hope it is helpful.
:-).
X = 2×3 + 3×(-2) ÷ 2+3
x = 6 - 6 ÷ 5
X = 0÷5
X = 0
Y = m1y2 + .m2y1 ÷2 + 3
Y = 2(-5) + 3×5 ÷ 2+3
Y = -10 + 15 ÷ 5
Y = 5 ÷ 5
Y = 1
The Coordinate of point P are ( 0 , 1 ).
Hope it is helpful.
:-).
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