Question

find the co-ordinate of the mid point of the line segment joining the point (4,-3) and (8,5)​

Answer 1

Answer:

let p(x,y) be mid point of AB.

by mid point formula, p(x,y)=((x₂+x₁)÷2,(y₂+y₁)÷2 )

                                    p(x,y)=((7-(-5))÷2,(-8+4)÷2)

                                    p(x,y)=((7+5)÷2,4÷2)

                                    p(x,y)=(12÷2,2)

                                    p(x,y)=(6,2)

                                    p(6,2)

Step-by-step explanation:

Answer 2

Answer:

Here the answer:

Step-by-step explanation:

Let the co-ordinates be (x,y).

And let (4,-3) be (x1,y1) and (8,5) be (x2,y2).

So x=x1+x2/ and y=y1+y2/2 ( Mid point formula).

So x=4+5/2 and y=-3+5/2

x=8/2 and y=2/2

For here x=4 and y=1.

So the co-ordinates of the mid point of points (4,-3) and (8,5) is (4,1).

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