Question

Find the co-ordinate of the midpoint of the line joining the points P(12, -4) and Q(8, -3) using formula.

Answer 1

Step-by-step explanation:

mid Point of (a, b) (c, d) =( (a+c) /2, (b+d) /2)

the co-ordinate of the midpoint of the line joining the points P(12, -4) and Q(8, -3)= ((1+8)/2, (-4-3)/2)

= ( 9/2,-7/2)

so, the co-ordinate of the midpoint of the line joining the points P(12, -4) and Q(8, -3) = (9/2, -7/2)

Answer 2

Given that :

PQ is a line segment

According to the question,

P = (12, -4)

Q = (8, -3)

To find :

The coordinates of midpoint

Solution :

We know that,

The mid point of the join of A(x₁, y₁) and B(x₂, y₂) is given by,

$\boxed{\bf P (x, y) = \bigg( \dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2} \bigg)}$

by substituting the values in the formula,

$\dashrightarrow\sf (x, y) = \bigg( \dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2} \bigg)$

$\dashrightarrow\sf (x, y) = \bigg( \dfrac{12 + 8}{2}, \dfrac{ - 4 - 3}{2} \bigg)$

$\dashrightarrow\sf (x, y) = \bigg( \dfrac{20}{2}, \dfrac{ - 7}{2} \bigg)$

$\dashrightarrow\sf (x, y) = ( 10, 3.5)$

Thus, the coordinates of the midpoint is (10, 3.5).